Find dy/dx for y=sinxtanx
Answers
Answered by
1
y= sinx tanx
dy/dx = sinx sec^2 x + tanx cosx
dy/dx = sinx sec^2 x + tanx cosx
Anonymous:
explain in detail
Answered by
1
dy/dx=sinx×d(tanx)/dx+tanx×d(sinx)/dx
=sinxsec^2x+tanxcosx
=sinx/cos^2x +tanx cosx
=tanxsecx+tanxcosx
=tanx(secx+cosx)
===========M☺
=sinxsec^2x+tanxcosx
=sinx/cos^2x +tanx cosx
=tanxsecx+tanxcosx
=tanx(secx+cosx)
===========M☺
thanks
u r in which class?
11
same here
so how did u give KVPY?
its in nov 2018
in 11
im to 12
oh ki
got it!
Similar questions