Question

Find dy/dx for y=sinxtanx

Answer 1

y= sinx tanx
dy/dx = sinx sec^2 x + tanx cosx

Answer 2

dy/dx=sinx×d(tanx)/dx+tanx×d(sinx)/dx
=sinxsec^2x+tanxcosx
=sinx/cos^2x +tanx cosx
=tanxsecx+tanxcosx
=tanx(secx+cosx)

===========M☺