find dy/dx for y= tan^-1(√1+x^2-x)
Answers
Answered by
1
Answer:
If y=tan
−1
[
x
1+x
2
−1
] prove that
dx
dy
=
2(1+x
2
)
1
Answer
We have,
y=tan
−1
(
x
1+x
2
−1
)
Let,x=tanθv=tan
−1
x
y=tan
−1
(
tanθ
secθ−1
)
y=tan
−1
(
sinθ
1−cosθ
)
y=tan
−1
(tan
2
θ
)=
2
θ
y=
2
tan
−1
x
dx
dy
=
2(1+x
2
)
1
Step-by-step explanation:
Hope it will help
Answered by
0
Step-by-step explanation:
hlo mate here's your answer
Answer
We have,
y=tan
−1
(
x
1+x
2
−1
)
Let,x=tanθv=tan
−1
x
y=tan
−1
(
tanθ
secθ−1
)
y=tan
−1
(
sinθ
1−cosθ
)
y=tan
−1
(tan
2
θ
)=
2
i hope its help you mark as brainlist plz
Similar questions