Question

find dy/dx for y=x³-3x²+12

​

Answer 1

Answer:

$y=3x^{2} -6x$

Explanation:

$y = \frac{dy}{dx} (x^{3} -3x^{2} +12)\\y= 3x^{3-1} -(2)3x^{2-1} +12(0)\\y=3x^{2} -6x$

Pls mark my answer as Brainliest

: )