Question

Find dy/dx from the principle y=√tanx​

Answer 1

Step-by-step explanation:

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Answer 2

$\mathbf{SOLUTION\:-}\\\\Y\:= \sqrt{TANX}\\\\\therefore \frac{DY}{DX}=\frac{D\:TAN^{-2}}{DTANX}\times\frac{DTANX}{DX}\\\\\therefore \frac{DY}{DX}=\frac{-2TAN^{-3}}{SEC^{2}X}\\\\\\\mathbf{HOPE\:IT\:MAY\:HELP\:YOU...}$