Question

find dy/dx given that y=(sin^ncosnx)​

Answer 1

Step-by-step explanation:

y = n sin"-x cos n: n-1

dy

dx

n sin"-'x cos na = n sin' x cos cos na

+sin"x. (-sin nx)

= n. sin"-x{cos nx cos x – sin x sin nx

n sinnjr{cos(n + 1)x}