Find dy/dx given that y= (Sin"x cosnx)
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Step-by-step explanation:
Y= n sinn-1 X COs nx
dy/ dx = n sinñ-1 . x cos cos nx
+sin"x. (-nsinnx)
= n. sin"-x{cos nx cos x n-1 sin x sin nx
n sinnjx{cos(n + 1)x}
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