Question

Find dy/dx given xcosy+ysinx=1​

Answer 1

Step-by-step explanation:

$\large \sf f(x) = xcosy + ysinx \\ \large \sf1 = xcosy + ysinx \\ \large \sf f(x) =xcosy + ysinx - 1 \\ \\ \LARGE\bf Now, \\\large \sf \frac{d}{dx} (xcosy + ysinx - 1) \\ \large \sf = x( - siny) + ycosy \\ \large \sf= - xsiny + ycosy$