Question

find dy/dx if 3x^2-2y^2=1​

Answer 1

Step-by-step explanation:

3x2−2y2=13x2-2y2=1

Differentiate both sides of the equation.

ddx(3x2−2y2)=ddx(1)ddx(3x2-2y2)=ddx(1)

Differentiate the left side of the equation.

−4yddx[y]+6x-4yddx[y]+6x

Since 11 is constant with respect to xx, the derivative of 11 with respect to xx is 00.

00

Reform the equation by setting the left side equal to the right side.

−4yy'+6x=0-4yy′+6x=0

Solve for y'y′.

y'=3x2yy′=3x2y

Replace y'y′ with dydxdydx.

dydx=3x2ydydx=3x2y

3x2−2y2=13x2-2y2=1