Physics, asked by atharvaaj, 10 months ago

Find dy/dx if:
(a)y = log x^2
(b) y=(x2 + 2)^10
(c)y= e^(x2 + 2)

Answers

Answered by aayushpathak20pe0um2
0

Answer:(a)y=logx^2

                   >dy/dx= 1/x^2

                 

                   (b)y=(2x+2)^10

                          >dy/dx=10(2)^9

 

                          (c)y=e^(2x+2)

                              >dy/dx=2e^(2x+2)

                               

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