Find dy/dx if:
(a)y = log x^2
(b) y=(x2 + 2)^10
(c)y= e^(x2 + 2)
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Answer:(a)y=logx^2
>dy/dx= 1/x^2
(b)y=(2x+2)^10
>dy/dx=10(2)^9
(c)y=e^(2x+2)
>dy/dx=2e^(2x+2)
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