Find dy/dx if, i) x^2 + 2xy + y^2 = 0
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2
Answer:
Explanation:
Differentiate the equation with respect to
x
, considering that based on the chain rule:
d
d
x
f
(
y
)
=
d
f
d
y
⋅
d
y
d
x
Thus we have:
d
d
x
(
x
2
+
x
y
+
y
2
)
=
0
2
x
+
x
y
'
+
y
+
2
y
y
'
=
0
solving for
y
'
:
y
'
(
x
+
2
y
)
=
−
2
x
−
y
y
'
=
−
2
x
+
y
x
+
2
y
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