Question

find dy/Dx if





....plzzzzzz answer this​

Answer 1

Answer:

solve using chain rule......

$we \: have \\ y = {sin}^{2} \sqrt{ {x}^{2} + 4 } \\ \frac{dy}{dx} = \frac{d {sin}^{2} \sqrt{ {x}^{2} + 4 } }{dx} \\ \: \: \: \: \: \: \: = 2sin \sqrt{ {x}^{2} + 4} \times \frac{d \sqrt{ {x}^{2} + 4 } }{dx} \\ \: \: \: \: \: \: = 2sin \sqrt{ {x}^{2} + 4 } \: . \frac{1}{2 \sqrt{ {x}^{2} + 4} } \times \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{d( {x}^{2} + 4 )}{dx}$

$\: \: \: \: \: \: = 2sin \sqrt{ {x}^{2} + 4} \: . \frac{1}{2 \sqrt{ {x}^{2} + 4 } } .2x$

= 2sin(√x²+4).x/(√x²+4)