Math, asked by pranavgk03, 9 months ago

find dy/Dx if





....plzzzzzz answer this​

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Answered by Trisha3010
3

Answer:

solve using chain rule......

we \: have \\ y = {sin}^{2}  \sqrt{ {x}^{2} + 4 }  \\  \frac{dy}{dx}  =  \frac{d {sin}^{2}  \sqrt{ {x}^{2} + 4 } }{dx}  \\   \:  \:  \:  \:  \:  \:  \:  = 2sin \sqrt{ {x}^{2}  + 4}  \times  \frac{d \sqrt{ {x}^{2} + 4 } }{dx}    \\  \:  \:  \:  \:  \:  \:  = 2sin \sqrt{ {x}^{2} + 4 } \: . \frac{1}{2 \sqrt{ {x}^{2}  + 4} }  \times \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \frac{d( {x}^{2} + 4 )}{dx}  \\

 \:  \:  \:  \:  \:  \:  = 2sin \sqrt{ {x}^{2}  + 4} \: . \frac{1}{2 \sqrt{ {x}^{2} + 4 } } .2x

= 2sin(√x²+4).x/(√x²+4)

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