find dy/dx if sin^2x + cos^2y = 1
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a)
(sinx)^2+ (cosx)^2=1
do dy/dx=
last ansrr
dy/dx=sin2x/sin2y
(sinx)^2+ (cosx)^2=1
do dy/dx=
last ansrr
dy/dx=sin2x/sin2y
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ammu300:
y=cot invers x nn ezthua. appo cot y=x
Answered by
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@karangrover12
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