find dy/dx if sin²y+cos(xy)=π
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2sinycosy.dy/dx +sin(xy).(y+dy/DX)=0
dy/DX{sin2y+sin(xy)}=-y.sin(xy)
day/dx=-y.sin(xy)/{sin2y+sin(xy)}
dy/DX{sin2y+sin(xy)}=-y.sin(xy)
day/dx=-y.sin(xy)/{sin2y+sin(xy)}
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