Find dy/dx if x^1/2+y^1/2=a^1/2
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Heya!
x½ + y½ = a½
DIFFERENTIATE ON BOTH SIDE'S W.R.T x WE HAVE
(1/2) x½-¹ + (1/2) y½-¹ × dy/dx = 0
x-½ + y-½ dy/dx = 0
y-½ × dy/dx = - x-½
y-½ dy/dx = -1/√x
dy/dx =( -1/√x ) × y½
dy/dx = -√y/√x
Oohhkk
Can u explain the last step.. how do you get -√y/√x?
Fine..... y-½ dy/dx = - x-½ ... y-½ dy/dx = -1/ ( x½)
y-½ dy/dx = -1/√x
dy/dx =- y½/√x
Oh ryt.. tysm:)
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