Find dy/dx if x^2+2xy+xy^2=5
Answers
Answered by
1
Answer:
dy / dx = - ( 2x + 2y + y² ) / ( 2x(1+y) )
Step-by-step explanation:
x² + 2xy + xy² = 5
⇒ d( x² + 2xy + xy²) = d(5)
⇒ d(x²) + d(2xy) + d(xy²) = 0
⇒ 2x dx + ( 2y dx + 2x dy ) + ( y² dx + x d(y²) ) = 0
⇒ 2x dx + 2y dx + 2x dy + y² dx + 2xy dy = 0
⇒ ( 2x + 2y + y² ) dx + 2x ( 1 + y ) dy = 0
⇒ 2x ( 1 + y ) dy = -( 2x + 2y + y² ) dx
⇒ dy / dx = - ( 2x + 2y + y² ) / ( 2x(1+y) )
Hope that helps
Similar questions