Find dy
dx
if
x=(2 cost t+ cos2t), y=(2sint +Sin2t)
Answers
Answered by
1
Answer
-(cost + Cos2t) / (Sint - sin2t)
Step-by-step explanation:
S.1 dy/dx = (dy/dt) / (dx/dt)
find dx/dt ( using chain rule)
find dy/dt (using chain rule )
then dy/dx = -(cost + Cos2t)/ (sint-sin2t)
is your answer
p.s : i am a student myself so please verify the answer first
Similar questions