find dy/dx, if x^2-xy^2-2y^2+4=10
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X^2-xy^2-2y^2-6=0
diffrentiating both side w.rt X we get,
2x -(x.dy/dx y^2 +y^2dy/dx x)-2.2y dy/dx=0
2x-(x.2y dy/dx + y^2)-4ydy/dx =0
2x -2xy dy/dx - y^2-4y dy/dx=0
2x- y^2=dy/dx (4y+2xy)
dy/dx= (2x-y^2)/(4y+2xy)
diffrentiating both side w.rt X we get,
2x -(x.dy/dx y^2 +y^2dy/dx x)-2.2y dy/dx=0
2x-(x.2y dy/dx + y^2)-4ydy/dx =0
2x -2xy dy/dx - y^2-4y dy/dx=0
2x- y^2=dy/dx (4y+2xy)
dy/dx= (2x-y^2)/(4y+2xy)
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