Find dy/dx if x^2+xy+y^2=3
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Answer:
-(3y + 2x)/x
Step-by-step explanation:
Differentiate both sides w.r.t. x
2x + (x* d/dx y + y* d/dx x) +2y = 0
2x + (x dy/dx + y) +2y = 0
2x + x dy/dx + y + 2y = 0
2x + x dy/dx + 3y = 0
x dy/dx = - 3y - 2x
dy/dx = - 3y - 2x/x
dy/dx = -(3x + 2y)/x
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