find dy/dx if x=a(n-sinn) , y=a(1+cosn)
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dx/dn=a(1-cosn)
dy/dn=-asin n
dy/dx=a(1-cosn)/-asin n
We have 1-cos n=2sin square n/2 & sin n=2sin n/2 cos n/2
Solving we get dy/dx=tan n/2
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