Question

*Find dy/dx, If x = cos t - cos 2t and y = sin t - sin 2t*​

Answer 1

dy/dx = (cos t - 2 cos 2t)/(-sin t + 2 sin 2t)

step-by-step explanation:

Given x= cos t - cos 2t , y = sin t - sin 2t

differentiating w.r.t ' t '

dx/dt = -sin t + 2 sin 2t , dy/dt = cos t - 2 cos 2t

dy/dx = (dy/dt)/(dx/dt)

= (cos t - 2 cos 2t)/(-sin t + 2 sin 2t)

therefore dy/dx = (cos t - 2 cos 2t)/(-sin t + 2 sin 2t)