Find dy/dx if x = e theta ( theta + 1/theta) and y = e -theta ( theta + 1/ theta
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do first dx/dθ then dy/dθ.then dy/dx.
we get x=eθ^2+e and y=e-θ^2-1.
dx/dθ=e2θ and dy/dθ= - 2θ.
∴ dy/dx=-1/e
we get x=eθ^2+e and y=e-θ^2-1.
dx/dθ=e2θ and dy/dθ= - 2θ.
∴ dy/dx=-1/e
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