find dy/dx if x = y²/2y + 1
Answers
Answered by
0
Explanation:
Given, x²+y² = 1
Differentiating w.r.t x,
2x+2y(y') = 0
⇒ x+y(y') = 0
Again differentiating w.r.t. x, we get
1 + y(y′′) + (y')(y′) = 0
1 + y(y′′) + (y′)² = 0
Similar questions