Find dy/dx if x2 + y2 = 3xy
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differentiating on both sides
2x + 2y*(dy/dx) = 3(x*(dy/dx) + 1*y)
collecting the terms of dy/dx on the left side we get;
{2y-3x}*dy/dx = 3y-2x
hence dy/dx = (3y-2x)/(2y-3x)
2x + 2y*(dy/dx) = 3(x*(dy/dx) + 1*y)
collecting the terms of dy/dx on the left side we get;
{2y-3x}*dy/dx = 3y-2x
hence dy/dx = (3y-2x)/(2y-3x)
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