Question

Find dy/dx if x2 + y2 = 3xy

Answer 1

differentiating on both sides

2x + 2y*(dy/dx) = 3(x*(dy/dx) + 1*y)

collecting the terms of dy/dx on the left side we get;
{2y-3x}*dy/dx = 3y-2x

hence dy/dx = (3y-2x)/(2y-3x)