find dy/dx if x²+y²-xy=4
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Hey mate here is your answer,
Differentiate with respect to x,
2x+2ydy/dx-{xdy/dx+y}=0
2x+2ydy/dx-xdy/dx-y=0
dy/dx(2y-x)=y-2x
dy/dx=(y-2x)/(2y-x)
Hope it will be helpful for you
Differentiate with respect to x,
2x+2ydy/dx-{xdy/dx+y}=0
2x+2ydy/dx-xdy/dx-y=0
dy/dx(2y-x)=y-2x
dy/dx=(y-2x)/(2y-x)
Hope it will be helpful for you
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