Question

find dy/dx if x³+y³+3x²y-3x=25.

Answer 1

=(x3-3×)=0

=(y3)

=(3x2y)

Ans=y3+3x2y

Answer 2

answer

3x^2.dy/dx+3y^2.dy/dx+6xy-3=0

dy/DX(3x^2+3y^2)+6(x.dy/dx+y.dy/DX)-3=0

dy/DX(3x^2+3y^2+6x)=3-6y

dy/DX=3-6y/3(x^2+y^2+2x)