find dy/dx if y^4 +tan y= x^3+ sec x by implict method
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Answer:
x=tan(y)
Step-by-step explanation:
Differentiate both sides of the equation.
d
d
x
(
x
)
=
d
d
x
(
tan
(
y
)
)
Differentiate using the Power Rule which states that
ddx[xn] is nxn−1 where n=1.1
Differentiate the right side of the equation
Differentiate both sides of the equation.
d
d
x
(
x
)
=
d
d
x
(
tan
(
y
)
)
Differentiate using the Power Rule which states that
d
d
x
[
x
n
]
is
n
x
n
−
1
Differentiate using the Power Rule which states that
d
d
x
[
x
n
]
is
n
x
n
−
1
where
n
=
1
.
1
Differentiate the right side of the equation.
Tap for more steps...
sec
2
(
y
)
dReform the equation by setting the left side equal to the right side.
1
=
sec
2
(
y
)
y
'
Solve for
y
'
.
Tap for more steps...
y
'
=
cos
2
(
y
)
Replace
y
'
with
d
y
d
x
.Replace
y
'
with
d
y
d
x
.
d
y
d
x
=
cos
2
(
y
)
d
x
[
y
]
Answered by
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