find dy/dx if y= a sin θ and x= b cosθ
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y = a sinθ
dy/dθ = a cosθ
x = b cosθ
dx/dθ = - b sinθ
so dy/dx = dy/dθ ÷ dx/dθ
= a cosθ / (- b sinθ)
= - b/a cotθ
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this answer is correct......
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