Question

find dy/DX if y =a^x+a^a​

Answer 1

Answer:

refer to the attachment for better understanding

Step-by-step explanation:

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Answer 2

Answer:

y=a  

x  

y

 

 

taking logarithm on both sides

logy=x  

y

loga

again we take logarithm on both sides

loglogy=y(logx)+logloga

taking derivative on both sides w.r. t x

logy

1

​  

.  

y

1

​  

.  

dx

dy

​  

=  

dx

dy

​  

logx+y.  

x

1

​  

+0

⇒  

dx

dy

​  

(  

ylogy

1

​  

−logx)=  

x

y

​  

⇒  

dx

dy

​  

(  

ylogy

1−ylogx.logy

​  

)=  

x

y

​  

 

⇒  

dx

dy

​  

=  

x(1−ylogx.logy)

y  

2

logy