find
dy/dx if y = cos(x^5 – 1)
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Answered by
6
Answer:
y = cos ⁵ ( x )
Differentiate using the chain rule , which states that d / DX [ f ( g ( x ) ) is f ' ( g ( x ) ) g ' ( x ) where f ( x ) = x ⁵ and g ( x ) = cos ( x ) .
To apply the chain Rule ,set u as cos ( x ) .
d / du [ u ⁵ ] d / dx [ cos ( x ) ]
Differentiate using the power role which states that d / du [ un ] is nu n -¹ where n = 5 .
5 u ⁴ d / DX [ cos ( x ) ]
Replace all occurance of u with cos ( x ) .
5 cos ⁴ ( x ) d ) DX [ cos ( x ) ]
The derivation of cos ( x ) with respect to x is - sin ( x )
5 cos ⁴ ( x ) ( - sin ( x ) )
Multiple - 1 by 5
- 5 cos ⁴ ( x ) sin ( x )
Answered by
2
Step-by-step explanation:
y = cos(x^5 – 1)
differentiating,
dy/dx=d{cos(x^5 – 1)}/dx
= {-sin(x^5-1)}{5x^4}
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