Find dy/dx if y=cos(x+y)
Answers
Answered by
16
y' = - sin(x+y) (1+y')
y' [1 + sin(x+y) ] = - sin(x+y)
y' = - sin(x+y) / [ 1 + sin(x+y) ] = - 1 + 1/[1 + sin (x+y) ]
y' = - 1 + 1/[1 + √(1-y²) ]
y' [1 + sin(x+y) ] = - sin(x+y)
y' = - sin(x+y) / [ 1 + sin(x+y) ] = - 1 + 1/[1 + sin (x+y) ]
y' = - 1 + 1/[1 + √(1-y²) ]
Similar questions