Question

find dy/dx if y=cosx+sinx+tanx​

Answer 1

Answer:

Given, y = (sin x)x +(cos x)tan x. Let u = (sin x)x and v = (cos x)tan x We have, y = u + v then d y d x = d u d x + d v d x dydx=dudx+dvdx ...(i) Now, u = (sin x)x Taking log on both sides, we get log u = x log sin x Differentiating both sides, with respect to x, we have Again, v = (cos x)tan x Taking log on both sides, we get log v = tan x [log cos x] Differentiating both sides with respect to x, we get