Question

find dy/dx if y=e^x^2tanx​

Answer 1

Step-by-step explanation:

y=e^x^2tanx

apply log on both sides

logy=x^2tanx

differentiate with respect to x

(1/y)(dy/dx)=[2tanx][x^(2tanx-1)][2sec(x^2)]

(dy/dx)=[e^x^2tanx][x^(2tanx-1)][2sec(x^2)]

Answer 2

Answer:

by product rule

e^x^2.2sec^x+2tanxe^x^2(2x)