Find dy
dx
if y= e^x. sin^-1x
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Answer:
Given that
y=e
x
.sinx
On differentiating, we get
dx
dy
=sinx
dx
d
e
x
+e
x
dx
d
sinx
dx
dy
=sinxe
x
+e
x
cosx
∴
dx
dy
=e
x
(sinx+cosx)
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