Math, asked by rishalx12, 4 months ago

find dy/dx, if y=extanx​

Answers

Answered by LaeeqAhmed
1

 \frac{dy}{dx}

  = \frac{d(e ^{x}  \tan x) }{dx}

 = e^{x}  \frac{d( \tan x )}{dx}  +  \frac{d(e^{x} )}{dx}  \tan x

 = e^{x}  \sec^{2} x  +  {e}^{x} \tan x

 = {e}^{x}  (  \sec^{2}x +  \tan x  )

HOPE THAT HELPS!!

Similar questions