Question

Find dy/dx, if y=log (2x+3)​

Answer 1

Step-by-step explanation:

$y = log(2x + 3) \\ \frac{dy}{dx} = \frac{d}{dx} ( log(2x + 3) ) \\ = \frac{1}{2x + 3} \times \frac{d}{dx} (2x + 3) \\ = \frac{1}{2x + 3} \times 2 \\ = \frac{2}{2x + 3}$