Question

Find dy/dx if y=log(cos^2x)

Answer 1

y=log(cos^2x)

dy/dx=d(log(cos^2x))/dx

applying chain rule

dy/dx=1/cos^2x*d(cos^2x)/dx

=1/cos^2x*2cosx*d(cosx)/dx

=1/cos^2x*2cosx*(-sinx)

=-sin2x/cos^2x

hope this helps

Answer 2

Explanation:

dy/dx=d/dx(log(cos^2x))

1/cos²x*d/dx(cos²x)

=1/cos²x*2cosxd/dx(cos x)

=1/cos²x 2cosx(-sinx)

=-2sin x/cos x

=-2tan x

mark it as the brainliest answer