Question

find dy/dx if y= log(sin 3x) × tan(2x)​

Answer 1

Step-by-step explanation:

in this we use chain rule

y= log(sin3x)×tan(2x)

dy/dx= (1/sin3x) × (cos3x) × 3 + (sec 2x)^2

dy/dx=3cot3x+(sec2x)^2

hope you understand this