Question

find dy/dx if y=log sinx​

Answer 1

Answer:

cot x

Step-by-step explanation:

y = log sinx

dy/dx = d/dx ( log ( sinx))

= 1/sinx * d/dx ( sinx) #d/dx ( log x) = 1/x#

= 1/sinx * cosx

= cosx / sinx

= cotx