find dy/DX if y= log ( x.ex)
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Answer:
dy/dx=(x+1)/x
Step-by-step explanation:
let take y=log(x.e^x)
we know that log(ab)=loga + logb
=>then logx + loge^x. (log e base e =1 and also loga^n=nloga so that xloge base e x)
=>logx + x
=>y=x+logx
=>differentiating on both sides with respective x
dy/dx =d/dx(x+logx)
=>dy/dx=1+(1/x) taking lcm
=>dy/dx =(x+1)/x
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