Question

find dy/DX if y= log ( x.ex)​

Answer 1

Answer:

dy/dx=(x+1)/x

Step-by-step explanation:

let take y=log(x.e^x)

we know that log(ab)=loga + logb

=>then logx + loge^x. (log e base e =1 and also loga^n=nloga so that xloge base e x)

=>logx + x

=>y=x+logx

=>differentiating on both sides with respective x

dy/dx =d/dx(x+logx)

=>dy/dx=1+(1/x) taking lcm

=>dy/dx =(x+1)/x