find dy/dx if y= sin( e ki power x)log x
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y=sin(e^x)logx
= sin(e^x) lnx/ln10
dy/dx = -((sin(e^x)/x)+lnx cos (e^x) e^x)/(ln10)²
= sin(e^x) lnx/ln10
dy/dx = -((sin(e^x)/x)+lnx cos (e^x) e^x)/(ln10)²
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