Question

Find dy/dx if y= (sin^n x Cos n x)​

Answer 1

Answer:

sin cos8yfugfihvojchuchxyxwf6w6fcgc6f7tc7tchcihx7txuihx8td8y

Answer 2

Given that :

$y = { \sin }^{n} x. { \cos}^{n} x$

D. w. r. x both the sides :

$\frac{dy}{dx} = { \sin }^{n} x.n { \cos}^{n - 1} x( - sinx) + { \cos }^{n} x.n { \sin }^{n - 1} x(cosx)$

$= > \frac{dy}{dx} = n.cosx \: { \cos }^{n} x. { \sin}^{n - 1} x - n \: sinx \: { \sin}^{n} x \: { \cos }^{n - 1} x$

I hope it will be helpful for you ☺

Fóllòw Më ❤