Math, asked by shyamal1022, 9 months ago

find dy/dx if y=sinx×cos2x

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Answered by Anonymous

Question:

$y = sinx \: cos2x$

Answer:

diff. w.r.t.x

$\frac{dy}{dx} = sinx \: cos2x \\ \\ \frac{dy}{dx} = sinx \frac{d \: \: }{dx} (cos2x)+ cos2x \frac{d}{dx} (sinx) \\ \\ \frac{dy}{dx} = sinx( - sin2x) 2+ cos2x(cosx) $

Formulae used:

$\star \: \frac{d}{dx} (x.y) = x \frac{d}{dx} (y) + y \frac{d}{dx} (x) \\ \\ \star \: \frac{d}{dx} sinx \: = cosx \\ \\ \star \: \frac{d}{dx} cosx = - sinx$

Answered by MarshmellowGirl

$\large \underline{ \red{ \boxed{ \bf \orange{Required \: Answer}}}}$

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find dy/dx if y=sinx×cos2x