Find dy/dx if y=sinx+cosx
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d(sinx)/dx = cos x
d( cos x)/dx = - sinx
So d( sinx + cosx)/dx = cosx - sinx
d( cos x)/dx = - sinx
So d( sinx + cosx)/dx = cosx - sinx
Answered by
1
y=sinx+cosx,
then
dy/dx =d(sinx)/dx + d(cosx)/dx,
dy/dx = cosx - sinx
then
dy/dx =d(sinx)/dx + d(cosx)/dx,
dy/dx = cosx - sinx
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