Find dy/dx , if y + siny = cosx
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Hi
Solution :- we differentiate the relationship directly with respect to X , i.e..,
dy/dx + d(siny)/dx = d(cosx)/dx
Which implies using chain rule
dy/dx + cosy* dy/dx = - sinx
this gives , dy/dx = - sinx/1 + cosy
where y is not equal to (2n+1)π
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@Raj❤
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