Question

find dy/dx if,

y=√x+1/x

​

Answer 1

$y = \sqrt{x + \frac{1}{x} } \\ \\ \frac{dy}{dx} = \frac{1}{2 \sqrt{x + \frac{1}{x} } } \frac{d}{dx} (x + \frac{1}{x} ) \\ \\ \frac{dy}{dx} = \frac{1}{2 \sqrt{x + \frac{1}{x} } } (1 - \frac{1}{ {x}^{2} } ) \\ \\ \frac{dy}{dx} = \frac{ {x}^{2} - 1 }{2 {x}^{2} \sqrt{x + \frac{1}{x} } }$