Question

find dy/dx if y= (x^2)/(9x-3)​

Answer 1

Answer:

y' = [(9x-3)(2x) - (x^2)(9)] / (9x -3)^2

= [18x^2 - 6x - 9x^2] / (9x-3)^2

= (9x^2-6x)/(9x-3)^2

= [3(3x^2 - 2x)]/(9(x-2)^2)

= 3x^2 - 2x/ 3(x-2)^2

that's the answer bro

:)