Find dy/dx if y=xlogx-x
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1
Step-by-step explanation:
1) xx (1 + log x)
2) log (ex)
3) log (e/x)
4) log (x/e)
Solution:
Given y = log xx
= x log x
Differentiate w.r.t.x
dy/dx = x(1/x) + log x
= 1 + log x
= log e + log x
= log (ex)
Hence option (2) is the answer
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