Find
dy/dx
in the following:
2x + 3y = sin x
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2
Answer:
dy/dx =(cos x - 2)/3
Step-by-step explanation:
Given that,
2x + 3y = sin x
Differentiating w. r. t, x, we get
2+ 3(dy/dx) = cos x
Or, 3(dy/dx) = (coax - 2)
Or, dy/dx =(cos x - 2)/3
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