Question

find dy/dx in x² + y² = 1 ​

Answer 1

2x + 2y(dy/dx) = 0

dy/dx = -x/y

Answer 2

Here ,

y=√1-x^2

so,

dy/dx = 1/2√1-x^2 (-2x)

dy/dx= -x/√1-x^2

Hope it's helpful to you!!!!