Find dy/dx interns of x,y if x^3+y^2-1=x^3y^3
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Hi Mate!!!
Differentiate both sides w.r.t. x
3 x² + 2 y ( d y / d x ) = 3 x² + y ³ + x³ 3 y² ( d y / d x )
=>
d y / d x { 2 y - x³ 3 y² } = y³
=>
d y / d x = {y³ / 2y - x³ 3 y ²}
=>
d y / d x = (y ²/ 2 - x³y)
!!!!!! Have a bright future ahead!!!!!!!
Differentiate both sides w.r.t. x
3 x² + 2 y ( d y / d x ) = 3 x² + y ³ + x³ 3 y² ( d y / d x )
=>
d y / d x { 2 y - x³ 3 y² } = y³
=>
d y / d x = {y³ / 2y - x³ 3 y ²}
=>
d y / d x = (y ²/ 2 - x³y)
!!!!!! Have a bright future ahead!!!!!!!
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